Black Market Crate Probability Experiment
Comments
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i really like your idea and the way that you are carrying out this so, firstly you deserve a big thanks and a pat on the back for doing this. i am sure the whole community will thank you if this turns out to be a fruitful investigation.
i don't know much about programming, but i am learning and use a bit of Visual basic, and when i am using random statements, even if i have a counter to weight the results, i use the "randomize" statement that uses the system clock as a benchmark to make theresult truly random.
this may or may not be the starting point you're looking for.
any corrections are welcome :P
mat
Using the system clock such as the following pseudo-code (based off the C++ equiv.)
seedRandomGenerator(getSystemTime());
is a common way for basic random number generation. More complicated algorithms are used for commercial products. It is very unlikely Z8 would use the algorithm you brought up. It may be possible to find the algorithm (and than the exact probability) by decompiling the application, however it depends if the number generation is handled on the client or server. If Z8 is smart it would be on the server, or they would do a hell of a job to prevent memory editing. Any assembly pros who might want to take on that challenge? -
It took me over 3000 crates to win an AUG-C. I hope this really messes up your stats mate

To be honest mate I reckon in total I've brought 5000-6000 crates (both ZP & GP) and only won 3 blackmartet guns in total (AUG-C, Kriss and DE-C). The same is true of all my friends and guild mates. I think the problem with your stats is that you're only taking into account the number of crates people have brought before winning a gun. This completely disreguards all the crates people have brought without winning (i.e. ran out of money and never won a prize).
I personally think the chance is about 1 in 2000, but I'm only basing that on the 10-12 people I play CF with. -
KronicHash wrote: »It took me over 3000 crates to win an AUG-C. I hope this really messes up your stats mate

1crate to win aug-camo... u mad? lol jk
1crate for Winchester
1crate for Anaconda-Adv
4crates for de-camo
30crates for AK Scope
45crates for Tommy
45crates for Kriss
80Crates for msg90
120Crates for M4-Custom
Man I want that damn awm ;[ -
Copy and pasted from another thread I posted on: "I have a feeling most people are lying about the number of crates it took them to win something", especially the "extremely lucky" ones who are able to win multiple times without many attempts.
I personally think your attempt in this experiment is nice, but it is useless if the data you get is not even real.
Anyway, I did not count crates exactly but I'll try to give an estimate:
Ak-Knife: 13
Gatling Gun: 180~
Anaconda Adv: 150~
AWM-Red Dragon: 10 Never got it
Desert Eagle-Camo: 120+ Never got it, used coupons
M4A1-Custom: 50~ Never got it
Kriss Super V: 35~ Never got it
Beretta AR70: 100~
Thompson: 220~ (three winchesters in those as well)
Desert Eagle-Scope: 5 Never got it
XM8-Adv: 30~ Never got it
MSG90: 15~ Never got it
Aug-Camo: 16
So lets see... Total prizes: 6 (If Winchester counts, then 9). Total attempted crates: About 944, but lets just say 900~1000.
And I think thats it. Good luck.
Edit: Wow, idiot bumped an seven month old thread. -
I gave people the percentile of .3% a long time ago.Hello all.
There are a lot of people on these forums who want to know the probability of getting a top prize in a crate. So I decided, it can't be too hard to find an estimate of the probability. Which brings me to this thread.
Aim.
To find out the probability of getting a top prize in a Black Market Crate.
Prediction.
My prediction of the probability would be around 0.3%. This takes into consideration the lucky ones (people who get it in <10 crates) and the unlucky ones (people who have bought over 150 crates and still have not got a top prize). It also takes into consideration that you get 3 prizes from each crate.
Method.
I will gather information from a range of Crossfire gamblers and use that to calculate an estimated probability using the following formula:
P=N/300 where P is the probability and N is the sum of crates each person bought to receive a top prize (all added together).
What I need from you.
I need anyone who has won a top prize to supply me with the information needed to calculate this elusive probability. I will take 100 samples into consideration for the conclusion (hence the N/300 bit, 100 samples x 3 prizes from each crate).
You are eligible to take place and send me information if:
- You have won a top prize from the Black Market. (M4-C, AK47-S, KRISS SUPER V, AWM-XMAS-ADV, DE-C, ANCND-ADV, AUG-CAMO, WINCHESTER/THOMPSON, M16-S)
- You can recall how many crates it took you to win this top prize. (To the nearest 10 crates if you cannot remember exactly)
Prize Won:
Number Of Crates Taken:
If you have more than one entry, please post them in the same post.
Data So Far.
Here is a list of the data collected so far. (For my own personal tracking use)
1. 80
2. 380
3. 2
4. 29
5. 48
6. 18
7. 3
8. 120
9. 890
10. 120
11. 200
12. 29
13. 26
14. 30
15. 4
16. 10
17. 50
18. 118
19. 30
20. 2
Conclusion.
This will be written once 100 people have supplied information.
Thank-you in advance for your time and information. -
I Opened a total of 683 crates and all i got is winchester
For the people that cant recall the number of crates they bought: Look at your zp and GP logs on your profile online. You can see there which expenses you made.
1000ZP/2000GP =>1
4500ZP/9000GP=>5
8000ZP/6000GP=>10
Just sum everything.
Tip: dont ever buy crates expecting to get a grand prize
Instead, be happy if you get a coupon.
This discussion has been closed.
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